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How would you do a probelm like the following?

it has (y^5)^3(y^3)^2
-----------------
(y^4)^4

It look s even more confusing written out like that
so in breif it has (yto the 5) to the 3(y to the 3)to the 2
on top of a division line and under the line is
(y to the 4) to the 4
everything that is in parenthasies is also in the parenthasies on the problem.

2007-01-17 19:03:02 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

First do the outer powers (multiply the exponents): (y^5)^3 = y^15, (y^3)^2 = y^6, (y^4)^4 = y^16.

Then you have (y^15 * y^6) / y^16.

Add exponents of terms multiplied, subtract exponents of terms divided, so the result is y^(15 + 6 - 16) = y^(21 - 16) = y^5

2007-01-17 19:18:59 · answer #1 · answered by gp4rts 7 · 0 0

Numerator={(y^5)^3}{(y^3)^2
=(y^15)(y^6)=y^21
Denominator =(y^4)^4=y^16
Hence Numerator/denominator=
=y^21/y^16
=y^21 X y^(-16)
=y^5 ans

2007-01-18 04:17:40 · answer #2 · answered by alpha 7 · 0 0

(y^5)^3(y^3)^2)/(y^4)^4 =
(y^15)(y^6))/(y^16) =
(y^15)(y^6))/(y^16) = y^5

2007-01-18 03:24:54 · answer #3 · answered by Helmut 7 · 0 0

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