How do you solve exponential functions?

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How do you solve exponential functions?

How do you solve the following exponential function?

3^(x+1) + 3^x = 36

Please help! Thanks.

2007-01-17 19:01:44 · 3 answers · asked by Palladium 1 in Science & Mathematics ➔ Mathematics

3 answers

3^(x + 1) + 3^x = 36
3*3^x + 3^x = 36
4*3^x = 36
3^x = 9
x = 2

2007-01-17 19:08:16 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋

3^(x+1) + 3^x = 36

3^x . 3 + 3^x = 36
3^x ( 3+1) = 36
3^x = 9 = 3 ^2
x = 2

2007-01-17 19:11:43 · answer #2 · answered by Srinath R 1 · 0⤊ 0⤋

first you should be attentive to that a million/5 raised to the destructive one potential is 5 (an identity) so 5^(x+3) = 5^(-a million) because of the fact the bases are the comparable so are their exponents sooo x+3 = -a million x=-4

2016-10-31 10:18:14 · answer #3 · answered by deliberato 4 · 0⤊ 0⤋