C3H5 (NO3)3 --> CO2 + H2O + O2 + N2
I dont know if im balancing it correctly, i need it to finish my stoichiometry problem...if you can help plz.
2007-01-17 18:25:38 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Ok, the question was
For the Reaction C3H5 (NO3)3 --> CO2 + H2O + O2 + N2.
87.5 g C3H5 (NO3)3 is used, How many grams of CO2 is produced?
2007-01-17 18:46:30 · update #1
I need to start by balancing.
2007-01-17 18:47:05 · update #2
Its a combustion reaction, for it produces carbon dioxide and water.
2007-01-17 18:51:36 · update #3
4C3H5(NO3)3 + 12CO2 + 10H2O + O2 + 6N2
by the way, the answer to your question is 50.9 grams of CO2.
solution:
87.5g of C3H5(NO3)3 (1mole C3H5(NO3)3 / 227g of C3H5(NO3)3) (12 mole of CO2 / 4 mole of C3H5(NO3)3) (44 g of CO2 / 1 mole of CO2) = 50.88105727g of CO2
but then we only need 3 significant numbers so it's 50.9g of CO2.
2007-01-17 20:53:24 · answer #1 · answered by banana_otaku 2 · 1⤊ 0⤋
Something doesn't seem right... C3H5 doen't make any sense and the (NO3)3 is 3 nitrate ions that would not bond to the C3H5.
Check your reactants and then I can help you.
2007-01-17 18:43:00 · answer #2 · answered by teachbio 5 · 0⤊ 0⤋
balanced:
4C3H5(NO3)3 --> 12CO2 + 10H2O + O2 + 6N2
You count all the species (atoms) on each side, and make sure they equal each other.
In this case, there are 12C's, 26H's, 12N's, and 36O's on both sides of this equation right hurr. Hope this helped. 8-)
2007-01-17 18:40:07 · answer #3 · answered by Phillip R 4 · 0⤊ 2⤋
you go on clubbung baby seals.
2007-01-17 18:37:41 · answer #4 · answered by ihateacaf0 3 · 0⤊ 2⤋