2007-01-17 17:34:56 · 6 answers · asked by lirael1019 1 in Science & Mathematics ➔ Mathematics
Not quite sure what this question is asking for.
2007-01-17 17:35:08 · update #1
NoName is right; what steps do I follow to arrive at (4, -7) though?
2007-01-17 17:55:48 · update #2
Well, the y-int. is (0,1) so I assume the symmetric point would either be parallel to it.....
odd question indeed.
2007-01-17 17:45:01 · answer #1 · answered by Anonymous · 0⤊ 0⤋
This equation is almost in vertex form, which is
y - 1 = -2(x - 2)^2
the vertex of the parabola, then is at (2,1)
The y intercept is found by setting x = 0.
y(0) = -7
The axis of symmetry of the parabola is x = 2
0 is 2 units to the left of 2, so 2 units to the right of 2 is 4
y(4) = -7, so the symmetrical point to (0,-7) is (4,-7)
2007-01-18 02:13:20 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
(4,-7) is the Symmetric Point.
2007-01-18 01:50:32 · answer #3 · answered by Srinath R 1 · 0⤊ 0⤋
The intercept is the cut with y axis.So putting x=0 y=-7
The symmetrical point is (0,7)
2007-01-18 07:18:46 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋
it is (4, -7). imagine folding the parabola. if you did, the y intercept (0,1) would lie over the point (4, -7)
2007-01-18 01:55:27 · answer #5 · answered by Sean S 2 · 0⤊ 0⤋
vertex(2,1)
the arms are down
y-intercept (0,-7)
symmetric pt to the y-intercept (-7,0)
2007-01-18 01:45:40 · answer #6 · answered by iyiogrenci 6 · 0⤊ 0⤋