What is the volume of a mole of gas at +20 degrees Celcius?

Question

I know it's 22.4litres at stp and 24.47litres at 25 degs C, but what about 20 degs C?
Got any references to back up the figure?
Thanks!

Answer 1

Using the ideal gas law one can calculate the volume of a known number of moles of an ideal gas at any combination of temperature and pressure.

PV = nRT
Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas rate constant, and T is the temperature (in Kelvin).

To convert degrees Celsius to Kelvin, add 273.15.
Kelvin = degrees C + 273.15

T = 20 degrees C + 273.15 = 293.15 K

Since you did not specify, I assume the pressure you are asking about is 1 atmosphere, 1 atm.
P = 1 atm

You want to know the volume of 1 mole of an ideal gas,
n = 1

And R is a constant (can have different values based on what units you use),
R = .082058 Liter*atm / mole*Kelvin

So solving the ideal gas law for volume,
PV = nRT
V = nRT / P

V = (1 mole) * (.082058 L*atm / mol * K) * (293.15) / (1 atm)
V = 24.06 Liters.

Answer 2

you know the formula

pV = nRT where T is absolute temperature

for stp t= 0 and T= 273 , for 20C t= 20 +273 = 293

so call V0 volume at 0 and V20 volume at t=20

you have pV0 = nRT0 and pV20 = nRT20

and V20/V0 = T20 /T0

and V20 = V0 *T20/T0

V20 = 22.4*293/273 =24.04 l

Answer 3

You can calculate ideal gas volume at 20C by plugging in to PV=nRT formula