2007-01-17 17:04:41 · 4 answers · asked by Car 1 in Science & Mathematics ➔ Mathematics
how long....until it hits the ground?
0 = -16t² + 95t + 63
t = (-95 ± √(95² - 4(-16)(63)))/-32
t = (-95 ± √13057)/-32
t = 6.5396 seconds (throwing out the negative solution)
2007-01-17 17:14:00 · answer #1 · answered by Jim Burnell 6 · 0⤊ 0⤋
Well if ur asking for the time taken to reach the ground i can answer like this
usethe equation s=ut+0.5gt^2
since the ground is 63ft beneath the cliff
using g =32ft/s^2
-63=95t-16t^2
16t^2-95t-63=0
-b+or-root(b^2-4ac)/2a
t=6.54 seconds
2007-01-17 17:28:40 · answer #2 · answered by SOAD_ROX 2 · 0⤊ 0⤋
Use the quadratic formula to find t! [-b +/- (sqrt of b^2 -4*a*c)]divided by 2*a
2007-01-17 17:22:00 · answer #3 · answered by lynn y 3 · 0⤊ 1⤋
what angle? are you trying to determine how far it will travel horizontally?
2007-01-17 17:17:45 · answer #4 · answered by Dr W 7 · 0⤊ 0⤋