n(n2-1)+n(n-1)
2007-01-17 16:46:00 · 5 answers · asked by sedillog 2 in Education & Reference ➔ Homework Help
i soo messed up and im sorry. the 2 is supposed to be squared.
2007-01-17 16:56:23 · update #1
=> N^3 -N+N^2-N
=> N^3+N^2-2N
2007-01-17 17:00:40 · answer #1 · answered by GuruG 2 · 0⤊ 1⤋
factor are"n and 2". I will explain. n(2n-1)+n(n-1) if multiplied out is (2n^2-n)+(n^2-n) simplified once it would be n^2+n^2-n, simplified again, 2n^2-n. This means 2(n x n)-n. the only factors are n and 2. Hope I explained well enough.
2007-01-18 01:00:51 · answer #2 · answered by Anonymous · 0⤊ 1⤋
Simplify first.
n( n^2 - 1 + n - 1)
n (n^2 + n - 2)
(n) (n - 1) (n + 2)
2007-01-18 00:56:25 · answer #3 · answered by ecolink 7 · 0⤊ 0⤋
I actually have no idea what this means...but here it goes...
multiply in...
(2n^2-n)+(n^2-n)
Add and subtract
3n^2-2n
Divide by n
3n-2
get the numbers all on one side
n=2/3
Sorry, I haven't taken math in a long time, so I'm not sure if that is even close to right
2007-01-18 00:54:57 · answer #4 · answered by rhodetryp21 3 · 0⤊ 1⤋
sorry i didnt read it right the first time.
multiply it out: n^3-n+n^2-1
factor out n: n(n^2-1)+(n-1)(n+1)
factor the n^2-1 : n(n-1)(n+1)+(n-1)(n+1)
*[think of (n-1)(n+1) as x and substitute... nx+1x and factor out the x.... x(n+1) and put the (x-1)(n+1) back in for x and you get the answer written below.
ANSWER:(n+1)(n+1)(n-1)
2007-01-18 00:56:38 · answer #5 · answered by ? 1 · 1⤊ 1⤋