HELP solving diff. eq!! (dy/dx) = [cos(x-y)]/[sin(x)sin(y)-1]?

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(dy/dx) = [cos(x-y)]/[sin(x)sin(y)-1]

How would I solve/integrate that?!

HELP

2007-01-17 16:06:35 · 2 answers · asked by abe_cooldude 1 in Science & Mathematics ➔ Mathematics

sin (x – y) = sin(x)cos(y) – cos(x)sin(x) = d(sin(x)sin(y)-1)
∫du/u = ln(u)
∫d(sin(x)sin(y)-1)/(sin(x)sin(y)-1) = ln((sin(x)sin(y)-1)) + C

2007-01-17 16:38:54 · answer #1 · answered by Helmut 7 · 0⤊ 1⤋

I think Helmut left out the chain rule. But he has the right idea: you need a "trick": an oh that works with trig formulas.

2007-01-21 00:15:09 · answer #2 · answered by a_math_guy 5 · 0⤊ 0⤋