What are the Formulas for:
nichkel (III) sulfite
silver bromide
copper (II) bicarbonate
nickel (II) selenide
manganese (IV) carbonate
lead (IV) nitride
tin (II) hydroxide
2007-01-17 15:58:23 · 3 answers · asked by aaaaaaaaaaaaaa555 3 in Science & Mathematics ➔ Chemistry
Any time you see a Roman numeral inside parens after a transition metal, this gives you the charge of the cation.
If you see the ending -ite or -ate, these are polyatomic ions that you must learn the rules for.
If you see the ending -ide, this is simply the ion of the element itself (except for hydroxide, which is OH-), ie. bromide is the anion of bromine.
When figuring out formulas from names, you must remember that charges must balance, ie + charges must = - charges
Look at tin (II) hydroxide: tin symbol is Sn, the charge is +2 since Roman numeral 2, and hydroxide is OH- (I memorized this).
In order to balance this, you need two OH- for each Sn: Sn(OH)2
Do this same process for silver bromide, nickel selenide, lead nitride
sulfite is (SO2)-1
bicarbonate is (HCO3)-1
carbonate is (CO3)-2
Good luck! It just requires some memorization of a few rules and about 10 or so polyatomic ions and you are in business!
2007-01-17 16:18:56 · answer #1 · answered by teachbio 5 · 0⤊ 0⤋
Im not going to tell you, but look at the charge on sulfite and if its anything other than 3 you switch Ni2s3
2007-01-17 16:06:42 · answer #2 · answered by COD 3 · 0⤊ 1⤋
a) Mercury II Carbonate b) Magnesium Nitrate e) Iron III Bromate f) Sodium Phosphate g) Ammonium Iodate h) Gold Acetate (do no longer take my be conscious in this one) (??) i) Zinc III Phosphate
2016-12-12 14:06:05 · answer #3 · answered by ? 4 · 0⤊ 0⤋