In Solving Equations by Factoring how would I do this problem. . .10u^3-5u^2=0?

Question

I'm not really sure how to do. I mean I tried to do because I know it has something to do with the Different of two squares but I just don't get it. Because my answers turn out all weird.

Answer 1

2u^3-u^2=0 (Divide by 5)

u^2(2u-1)=0 (Factor u^2) (You could also divide by u^2 here and go straight to the answer.. 2u=1)..

u^2(2u-1)+1=1 (Add 1)

2u-1+ 1/u^2 = 1/u^2 (Divide by u^2)

2u=1 (Subtract 1/u^2, then Add 1)

u = 1/2 (Divide by 2)

Answer 2

Step 1 Factor (Divide) out 5u^2, from both terms
5u^2(2u-1)=0
Step 2 We have two terms multiplied together that equal zero, therefore at least one of the terms have to equal zero (Zero Product Property).
5u^2=0 or 2u-1 = 0
Step 3 Solve both equations
5u^2=0, therefore u=0
2u-1=0, 2u=1, u = 1/2
Step 4 Our answers are 0 and 1/2, check by substituting 0 or 1/2 into the original equation.
or if you have a graphing calculator, graph the original equation and you will see the x intercepts (where graph crosses x axis) are 0 and 1/2.

Answer 3

WHAT'S your answer .i got 5u(2u+1)(u-1)
2u+1=0 u-1=0
-1 -1 +1 +1
2u=-1
/2 /2
u=-1/2 . u=1

Answer 4

10u^3 - 5u^2 = 0
10u^3 = 5u^2
2u^3=u^2
u^2/u^3=2
u=2^1.5
u=2.828