If I was given 10 mL and 2 M of acetic acid and 2.50 g of sodium bicarbonate what is my balanced equation what is my limiting reagent and theoretical yield.
2007-01-17 13:02:54 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Atomic weights: C= 12 H = 1 O = 16 Na = 23 HC2H3O2 = 60 NaHCO3 = 84
NaHCO3 + HC2H3O2 ===> NaC2H3O2 + CO2 + H2O
Let the solution be called s; let acetic acid be called A; let sodium bicarbonate be called B.
10mLs x 2molA/1000mLs = 0.02 molA
2.50gB x 1molB/84gB = 0.030 molB
So acetic acid is the limiting reagent. You see the balanced equation. You forgot to mention theoretical yield of what. You will get 100% yield of NaC2H3O2, H2O, and CO2 based on all these reactions running to completion (as they will), with a little bicarb left over.
2007-01-17 13:40:07 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
to find the limiting reagant times the molarity by the volume for both acetic acid and the sodium carbonate. but first balance the equation. make sure that you have the same number of ions on both sides
2007-01-17 13:26:28 · answer #2 · answered by Marie F 2 · 0⤊ 0⤋