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math hw...plz help. dont wory, there is more to the hw so ur not doing it either way. thanxex

2007-01-17 13:01:58 · 6 answers · asked by catfight_007 1 in Education & Reference Homework Help

6 answers

What grade are you in? Don't you go to school so they can teach you this type of stuff?

2007-01-17 13:06:12 · answer #1 · answered by shortcutie2708 2 · 0 0

First - to find the GCF - make a factor tree.
34. It's even, so divide it by 2.
34/2 = 17 & 2
Both 17 and 2 are prime numbers. 17 is a bigger number, thus that's your answer

If you don't get what i mean, practice it till you do.

To the person that said:
"you need two numbers" (not exactly as stated)
That's used to find common multiples.

To the person that said:
"Don't you learn this at school"
No. (whacks you with a hammer) If he did, he wouldn't be asking this now. He was taught it, but he didn't learn it, don't be a jerk.

To the person that said
"2, i'm not very good at math" (not exactly as stated)
That's the Lowest common factor

To the person that said
"17"
You are correct! That's the Greatest common factor!

Now gimme a best answer =P

2007-01-17 13:09:01 · answer #2 · answered by salami_sandwich2 1 · 0 1

you're desirous to discover what instantly ahead decision can both one in all 39 and 26 be divided. to that end, it truly is going to likely be thirteen. generally you should use 2, 2 etc and then only multiply them altogether. besides the undeniable fact that, you could't do this for this question. So only save attempting and also you'll discover that the in reality instantly ahead decision both 39 and 26 might want to be divided by is thirteen. this promises you a relax of three and a couple of respectively and there are not any extra instantly ahead decision for 3 and a couple of.

2016-11-25 00:19:31 · answer #3 · answered by ? 4 · 0 0

I'll say it again.

You cannot have a GCF for one number. You need two. Hence the word "common"

2007-01-17 13:05:41 · answer #4 · answered by amylee1178 2 · 0 0

I could be wrong but I think its 2 ? I was never any good at math , sorry . 8 /

2007-01-17 13:06:22 · answer #5 · answered by Anonymous · 0 0

17.

2007-01-17 13:06:57 · answer #6 · answered by Anonymous · 1 0

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