2007-01-17 12:56:04 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
i am glad i am an electronic engineer and not a chem engineer
2007-01-17 13:00:19 · answer #1 · answered by satnlafsasurot@sbcglobal.net 2 · 0⤊ 0⤋
Two. Hg2SO4 <===> Hg2^2+ + SO4=
The first is mercurous ion.
2007-01-17 13:00:55 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋
When Hg2SO4 breaks apart, it gives one Hg2(2+) ion and one SO4(2-) ion. Actually a tricky question because mercury (I) is an exception!
2007-01-17 13:00:51 · answer #3 · answered by klammdog2002 1 · 0⤊ 0⤋
ions are thoroughly sequential in step with unit of particulate factors. go away NH4 as 4 in step with numerator so [(4x4)4)-4(4x4)] now even as the ions themselves are electrically charged you should keep in mind that to dissolve in water you've were given to consider temperature and magnetism which all carry about gravitational rigidity of concurrence which signifies that AO4 might want to be delivered round like this (AOs4A)-(NH4) yet be advised 4 is negligible in accordance with ion count number 4 will continually have a distinct fee even no matter if it continues to be 4. ion count number might want to be restricted to electron valence in the objective atom. so one electron might want to be 2 ions in step with dissolution sequencer. take ions as I for now I equates to [3/(7)/4]=NH(AO) you get 5.(5HA){NO} please word HA NO characterize places in this sequencer (5.5H)/(AO4) equates to at least a million.5a ion in step with particulate or P1=a million.5 equated to {(NH)(3)}/(4)=(O)
2016-11-25 00:17:58 · answer #4 · answered by ? 4 · 0⤊ 0⤋