geometric proof??

Question

omg I suck at proofs!!! *cries* anyhow, I'm not sure how to do this one, and it has to be a two column proof..can anyone help me?

here's the link to the diagram and all:
http://i14.tinypic.com/4br44ld.jpg

please help?

Answer 1

Because CD and AB bisect each other, we know that

CE = ED, and AE = EB

We know that angles

@AEC = @BED

Therefore, trianges

AEC = BED

and that means angles

@CAE = @DBE

which is the necessary condition that lines

AC || BD

Answer 2

AB and CD bisect each other ▐ Given
m AE = EB ▐ AB is bisected at E
CE = ED ▐ CD is bisected at E
ΔCEA ≡ ΔDEB▐ Side-Angle-Side
m AB || CD ▐ Alternate interior angles are equal

Answer 3

1) AB and CD bisect each other by given
2) CE=ED by midpoint postulate
3) AE=EB by midpoint postulate
4) 5) triangle CAE = triangle BDE by SAS
6) 7) CA // BD by the converse of alternate interior angles

Answer 4

In triangles AEC and BED
EC=ED (given)
EA=EB (Given)
and therefore the triangles are equal in all rspects (SAS congruency}
Therefore,