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2007-01-17 12:02:27 · 2 answers · asked by lAr0$A 2 in Science & Mathematics Mathematics

2 answers

Do you mean √(x+11) + 1 = x?

Subtract 1:
√(x+11) = x - 1
Square both sides:
x+11 = x² - 2x + 1
Subtract x+11:
0 = x² - 3x - 10
Factor:
0 = (x-5)(x+2)

So your possible solutions are x=5 and x=-2. I say possible, because one of the transformations we did (squareing both sides) was not invertible. So we check:

x=5:

√(5+11) + 1 = √16 + 1 = 4+1 = 5, so this solution is correct.

x=-2:

√(-2+11) + 1 = √9+1 = 3+1 = 4 ≠ 2, so this solution is not correct.

Thus the unique solution is x=5.

2007-01-17 12:46:06 · answer #1 · answered by Pascal 7 · 1 0

The above answer is incorrect! do no longer reproduction that. First you subtract a million from the two facets. (rad x +11)= x-a million J did x+a million which will deliver approximately the incorrect answer. Then sq. the two facets. x+11 = (x-a million)^2 x+11=x^2-2x+a million Then deliver all of it to one area x^2-3x-10=0 then you incredibly ingredient it (x-5)(x+2)=0 Your solutions are 5 and -2

2017-01-01 08:20:26 · answer #2 · answered by Anonymous · 0 0

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