The yintercept
of the line passing through ( 1,1) that is perpendicular to the line
2x - y = 4 is:
a. ( 0,2 )
b. ( 0,- 4 )
c. ( 3 )
2 0,
d. ( 0,- 1)
e. None of the abov
2007-01-17 11:44:16 · 4 answers · asked by kia_the_lovely_elven_warrior 2 in Science & Mathematics ➔ Mathematics
find the slope of the given equation....
Y=2X-4
slope is 2
the slope of the line passing through (1,1) that's perpendicular to that is -1/2 (opposite inverse)
equation is Y= -1/2X+B
where B is the Y-int
1= -1/2+B
B=1.5
(0,1.5)
so E
2007-01-17 11:53:23 · answer #1 · answered by Spearfish 5 · 0⤊ 0⤋
First rewrite the 2x-y=4 in the form of "y=mx+b". You get y = 2x-4. So the slope of the line is 2. A lines perpendicular to each other have slopes that are negative reciprocals of each other. So the slope of the line we're looking for is -1/2. It's equation would therefore be y = (-1/2)x + b for some as of yet unknown value of "b", the line's y-intercept.
We're told that this line also passes through point (1,1). We can use this to find "b". Plug it into the equation and you get 1 = (-1/2)*1 + b, or b = 3/2. This is the line's y-intercept. So the point where it crosses the y-axis is (0, 3/2).
2007-01-17 19:55:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2x-4=y so the slope is 2.
The slope of the perpend. is-1/2 and passing through (1,1)
y-1=-1/2(x-1) so y=-1/2x +3/2 So the intercept is( 0,3/2) none of the above
2007-01-17 19:53:06 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
e
2007-01-17 19:51:57 · answer #4 · answered by johnmcdonald12000 1 · 0⤊ 0⤋