A woman weighs 495 N and wears shoes that touch the ground over an area of 412 cm.?

Question

How does the pressure change when she stands only on one foot?

Answer 1

Pressure is the force exerted per unit area,
Pressure = Force / Area

You are given the woman's weight (which is a force) as 495 Newtons.
You are given the area of the woman's shoes (412 cm^2).

Pressure = 495 N / 412 cm^2 = 1.20 Newtons per square centimeter

Or you could first conver the area you are given into square meters.
100 cm x 100 cm = 1 m x 1 m = 1 square meter = 10,000 cm^2
412 cm^2 = .0412 m^2

Pressure = 495 Newtons / .0412 m^2
Pressure = 12000 Newtons per square meter
Pressure = 12000 Pascals
Pressure = 12 kiloPascals

Answer 2

Pascals formula: stress = stress / (floor section) , stress in newtons and floor section in meters^2 P = 850n / ( 725 ^ (a million/2) cm ) ^2 = 850n / ( 725 ^ (a million/2) * 10^(-2) m) ^2 = 11,724 Pascals = 11.724kPa