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The ones rumored to be selected for the upcoming All-Stars edition are:

Season 1 - Joe & Bill (Team Guido) (3rd place)
Season 3 - John Vito & Jill (5th)
Season 5 - Sharla & Mirna (Schmirna) (6th), Colina & Christie (2nd)
Season 6 - Freddy & Kendra (winners)
Season 7 - Rob & Amber (Romber) (2nd), Uchenna & Joyce (winners)
Season 10 - Dave & Mary (coalminer & wide) (6th)


Not selected:
Season 1 - Rob & Brennan (lawyers & best friends) (winners)
Season 5 - Chip & Kim (winners)
Season 9 - BJ & Tyler (the hippies) (winners)

Can anyone confirm these rumors, or add names to either list? Thanks.

2007-01-17 11:37:53 · 3 answers · asked by xander 5 in Entertainment & Music Television

The teams have already been announced 2 days ago (didn't know about it). They are as follows (11 teams):

Season 1 - Joe and Bill (life partners) (3rd place)
Kevin and Drew (fraternity brothers) (4th)

Season 2 - Oswald & Danny (best friends) (4th)

Season 3 - Ian and Teri (Vietnam war veteran & wife) (2nd)
John Vito & Jill (formerly dating) (5th)

Season 5 - Charla & Mirna (cousins) (6th)

Season 7 - Rob & Amber (married) (2nd)
Uchenna & Joyce (married) (winners)

Season 9 - Eric (2nd) & Danielle (7th) (from separate teams, dating)

Season 10 - David & Mary (coal miner & wife)
Dustin & Kandace (beauty queens)

I'm really surprised that no one from seasons 4 and 6 were selected because they were the most interesting teams, IMO. I would have selected Reichen & Chip, & Freddy & Kendra. But these teams are still really interesting to watch though. I'm rooting for Team Guido cos they are really nice people in reality :-)

2007-01-17 23:50:38 · update #1

3 answers

I haven't heard anything, but haven't Rob and Amber done enough reality shows? They did Survivor, Survivor All-Stars, Amazing Race, and now Amazing Race All-Stars! I hate Rob; he's so annoying.

2007-01-17 11:51:44 · answer #1 · answered by SkiGirl04 4 · 1 0

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2016-10-31 09:47:21 · answer #2 · answered by Anonymous · 0 0

sounds good

2007-01-17 12:35:20 · answer #3 · answered by shorty 6 · 1 0

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