when i factor this problem 12x^3+2x^2-60x-10 is the answer (2x^2-10)(6x+1) ????

Question

When i foiled that answer out it worked back to the original promblem. But I dont know why it worked with the +1 at the end...? am i allowed to out in +1 in (6x+1)???
Hope you understand what i am asking, thank you!

I ment to say am I allowed to PUT in +1

Answer 1

You did it all correctly:

Factor out a 2x² from the first two terms:
2x²(6x + 1) -60x - 10

Now factor -10 from the last two terms:
2x²(6x + 1) -10(6x + 1)

Factoring out the common 6x + 1:
(2x² - 10)(6x + 1)

Checking using FOIL:
First: 2x² * 6x = 12x^3
Outer: 2x² * 1 = 2x²
Inner: -10 * 6x = -60x
Last: -10 * 1 = -10

This all matches to the original:
12x^3 + 2x² - 60x - 10

Note, you could pull an extra 2 out of the first expression, if you want to be complete.
2 ( x² - 5 )( 6x + 1 )

Answer 2

The trick is to discover 2 numbers which you will multiply to get 8 (2x4) and upload to get 9. The numbers 8 and a million would desire to are evoked. then you definitely replace those numbers into the equation somewhat than 9x. for this reason the expression turns into 2x^2 + 9x + 4 2x^2 + 8x + x + 4 you will desire to then take out consumer-friendly components 2x(x+4) + a million(x+4) (increasing this expression would desire to provide you the unique expression) the main suitable answer is (2x +a million)(x+4)

Answer 3

12x^3 + 2x^2 - 60x - 10

First: when you have 4 terms - group "like" term...

(12x^3 + 2x^2) - (60x - 10)

Sec: factor both sets of parenthesis...

2x^2(6x + 1) - 10(6x + 1)

(6x + 1)(2x^2 - 10)

Yes-your answer is correct :-)

Answer 4

Good, but:
= 2{6xxx +xx –30x –5} = 2{xx·(6x+1) –5(6x+1)} = 2(6x+1)(xx-5) =
= 2 (6x+1) (x-sqrt5) (x+sqrt5);

Answer 5

the problem has to be further factorised to :

2(x² - 5)(6x+1).

I'm not sure what you mean by "out in" +1, but it's better to use Synthetic Multiplication to expand the terms.