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Solve for b.
P=a+b-c
answer is: P/b=a-c
AM i RIGHT????

2007-01-17 10:43:14 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

you're solving for b -.-
so it should be "b = something"
b = P+c-a

2007-01-17 10:47:49 · answer #1 · answered by Taras 2 · 0 0

NO

If you wanna solve for b, you need to get b on one side of the equal sign by itself.

Not only that You divided both sides by b, but b wasn't being multiplied by anything. You use division to undo multiplication.

The way to solve your problem is this. Knowing we want b by itself and seing a +a and -c we can very simply get b by itself.

We undo addition by subtraction and vice versa. So to undo the +a we want to subtract a from both sides as follows:

P (-a) = a + (-a) + b -c The +a and -a on the right cancel

So we now have...

P - a = b - c

We're not done. To undo the -c we have to add. So we'll add +c to both sides as follows:

P - a (+ c) = b - c (+ c) The -c and + c on the right cancel

So we have...

P - a + c = b

That is your answer, notice b is by itself.

Hope this helps, Good Luck with your Math.

2007-01-17 18:46:49 · answer #2 · answered by Chaney34 5 · 0 0

No.

P = a + b - c

P + c = a + b - c + c (add c to both sides does not change the equation)

this gives P +c = a + b (the +c - c = 0)

P + c - a = a + b -a (adding a does nothing to the equation)

P + c -a = b (a - a = 0)

2007-01-17 18:49:27 · answer #3 · answered by Modus Operandi 6 · 0 0

You are wrong.

Given
P=a+b-c

Subtract a from both sides.
P-a=b-c

Add c to both sides.
P-a+c=b

Solution
b=P-a+c

2007-01-17 18:56:08 · answer #4 · answered by Anonymous · 0 0

solving for b is p-a+c =b

2007-01-17 18:48:24 · answer #5 · answered by calf_baby 2 · 0 0

no if youare solving for b, you want to get it by itself. P+c-a=b.

2007-01-17 18:48:38 · answer #6 · answered by Anonymous · 0 1

No, b= P-a +c

2007-01-17 18:47:58 · answer #7 · answered by Anonymous · 0 0

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