i have a math question i need help one can anyone help my pllease???

Question

Together they cost .40 cents
A nibblet cost three times as much as a cibbler
6 cibblers cost more then one wibbler
A nibblet plus 2 cibblers cost less then a wibbler

What is the cost of each type of candy?

Answer 1

If you are limited to whole cents, this problem does not have a solution.

If fractions of a cent are allowed:

cibbler = 4.25 cents
nibblet = 12.75 cents
wibbler = 23 cents

check:

together they cost 40 cents
c + n + w = 4.25 + 12.75 + 23 = 40 cents

a nibblet costs three times as much as a cibbler
n = 12.75 cents
3c = 3(4.25) = 12.75 cents

6 cibblers cost more than one wibbler
6c = 6(4.25) = 25.5 cents
w = 23 cents
25.5 > 23

a nibblet plus two cibblers costs less than a wibbler
n + 2c = 12.75 + 2(4.25) = 21.25 cents
w = 23 cents
21.25 < 23

Answer 2

I think you're missing a few words or numbers here. Because this doesn't work out.

Let n be the price of a nibblet, c be the price of a cibbler, and w be the price of a wibbler. Now just translate the sentences into equations.

"Together they cost .40 cents". When WHAT'S together? One of each? If so, n+c+w = 40. I'm also assuming you mean "40 cents" and not ".40 cents" which would be four tenths of a cent.

"A nibblet cost three times as much as a cibbler", so n = 3c.

"6 cibblers cost more then one wibbler", so 6c > w.

"A nibblet plus 2 cibblers cost less then a wibbler", so n+2c
You have two equations and two inequalities. This doesn't really tell you much. You need to have these better defined to get a better answer. Again, I think you forgot to type some info.

Answer 3

Ok.. you need to break this down into equations first

When you say together they cost .4 cents, that implies TWO items not the three.. I think that line was supposed to go second and refers to a Nibbet and a Cibber

So with that we get

N + C =.4
and with line 2
3C = N

Substitute for N and you end up with 3C + C = .4 or the value of your choc. Cibbler is ten cents.

That makes your Nibblet .3 or 30 cents

Your Wibbler must be less then 6 Cibbers (60 cents) and more then the cost of a nibblet and 2 cibbers (50 cents).

Soooooo...............

If you are not using pennies the cost of a Wibbler must be 55 cents. If you are using pennies the Wibbler will set you back between 51 and 59 cents.

ok..? (Again this is based on the first line referring to Nibblets and Cibblers combined).

.

Answer 4

Here's my 40 cents worth:
N = Nibblet
C= Cibbler
W = Wibbler

N + C + W = 40 cents

N = 3C, Therefore:

3C + C + W = 40 cents

N + 2C < W or
3C + 2C < W or
5C < W

Since 6C > W

We know that W has to reside somewhere between 5C and 6C. Can we assume that it is at it's midpoint or 5.5C?

3C + C + 5.5C = 40 Cents

C = 4.27 Cents

I think my logic may be flawed, and I also think that there is information missing.
I hope that someone solves it.

Answer 5

n + c + w = 40 cents

n = 3c so 3c +c +w =40 cents...and 4c +w = 40 cents

6c > w

n + 2c < w

so n +2c and 3c + 2c so 5c< w< 6c
it will never come out even cents, because it is a fraction between.

Answer 6

n + c + w = 40 cents

n = 3c

6c > w

n + 2c < w

You are dealing with two different things EQUATIONS and INEQUATIONS, so you can't substitute these into any different equation or inequation.

If the formulas above equaled each other (i.e. the greater and lesser signs were removed) then ...

n = 3c

6c = w

n + 2c = w

6c = n + 2c

n = 4c

So it can't work out because you have n = 3c and n = 4c

Answer 7

At first that seemed easy t me then it sounded confusing. What grade are you in?