I have i math question i need help can anyone help me please!!!?

Question

Find out the cost of each candy- Nibblet wibbler and Cibbler

Together they cost .40 cents
A nibblet cost three times as much as a cibbler
6 cibblers cost more then one wibbler
A nibblet plus 2 cibblers cost less then a wibbler

What is the cost of each type of candy?

Answer 1

These are harder than regular systems of equations. The only way I know to do them is to think through them.

Let:

n - cost of a nibblet
w - cost of a wibbler
c - cost of a cibbler

Then, "Together they cost .40 cents":

n + w + c = 0.4

"A nibblet cost three times as much as a cibbler":

n = 3c

"6 cibblers cost more then one wibbler":

6c > w

"A nibblet plus 2 cibblers cost less then a wibbler":

n + 2c < w

It's easiest to work with the equations first, so take the 2nd equation and use it to plug in 3c for n in the first equation:

3c + w + c = 0.4

Which simplifies to:

4c + w = 0.4

Also, you can plug in 3c for n in the fourth equation:

3c + 2c < w

Which becomes:

5c < w

We also have w < 6c from the third equation.

If a wibbler were worth exactly 5 cibblers, then the first equation would be:

3c + c + 5c = 0.4
9c = 0.4
c = 0.0444

Which doesn't come out to be an even number of cents. But if a wibbler were equal to 6 cibblers, then we'd have:

3c + c + 6c = 0.4
10c = 0.4
c = 0.04

A cibbler would cost 4 cents. Then a nibblet would cost 12 cents, and a wibbler would cost 24 cents, and together they'd cost 40 cents.

So that's my guess. There's a little problem with it though. The sentence "6 cibblers cost more than one wibbler" isn't true; actually 6 cibblers cost exactly one wibbler.

However, any other way I try to work it out, I get decimals that are longer than 2 digits, so I'm going to stick with this answer.