I f standard atmospheric pressure is exerted upon a school building and the surface area of the top?

Question

of the building is 130 m x 60 m, what is the force of air molecules pusing down upon the building from above?

Answer 1

1 atmosphere = 101.325 kPa

For this I will use 100kPa = 1 x 10^5 N/m²

Area = 130m x 60 m = 7,800m² = 7.8 x 10^3m²

Now Pressure = Force / Area, so Force = Pressure x Area

Force = 1 x 10^5 N/m² x 7.8 x 10^3m² = 7.8 x 10^8 N

Remember, the same pressure is exerted on the ceiling under the roof.

Answer 2

Atmospheric pressure is 101,325 N/m^2. The area of the top of the building is (130 m) * (60 m) = 7800 m^2. The total force is the pressure times the area: 101,325 N/m^2 * 7,800 m^2, which equals 790, 335,000 Pa (790 MPa). Of course the same pressure is exerted upwards by the air inside the building, so the net force is 0.

Answer 3

Atmospheric pressure is around 98066.5 Pascals, so if your school building has a roof surface area of 130m X 60m, the force exerted on the roof is 7800 m^2 X 98066.5 Pascals = 764918700 Newtons, or a little over 171 million pounds of force.