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Calculate the Ksp value for bismuth sulfide, Bi2S3, which has a molar solubility of 1.0*10da-15mol/L @ 15C

2007-01-17 06:46:43 · 2 answers · asked by Arnold M 1 in Science & Mathematics Chemistry

2 answers

OK...When bismuth sulfide dissolves, it will produce 2 Bi3+ ions and 3 S2- ions. So, the formula for the Ksp is:

Ksp=[Bi3+]^2[S2-]^3

The molar solubility of 1 X 10^-15 mol/L says that in a saturated solution that many moles of the original compound dissolves in a liter. So, the concentration of Bi3+ ions will be 2 X 10^-15 M, and the sulfide ion concentration will be 3 X 10^-15 M.

Substitute those values in the Ksp equation and solve for your answer.

2007-01-17 07:00:36 · answer #1 · answered by hcbiochem 7 · 1 0

Bismuth Sulfide

2016-10-06 04:16:51 · answer #2 · answered by jaspal 4 · 0 0

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