math question?

Question

cones = .90
bars = .75
$13.50 was spent and 4 more cones than bars were bought.
How many cones were bought

Answer 1

You've got to set up two equations to solve this problem. So let's see what we've got.

An x amount of cones were bought (at .90 each) and a y amount of bars were bought (at .75 each), totalling $13.50. We can write that out as:

0.9x + 0.75y = $13.50

OK? Next we know that 4 more cones (x) than bars (y) were bought. We can write this out as:

4+x = y

Does that make sense? Look at those two equations again and how I got them, because that's the key point in understanding this part of Algebra II.

Now that we have our two equations we'll use the Substitution Method to solve.

0.9x + 0.75y = $13.50
x = y + 4

Let's plug in our value for x in the second equation, (y + 4), in for x in our first equation.

0.9(y + 4) + 0.75(y) = $13.50

Let's simplify:

(0.9 * y + 0.9 * 4) = 0.9y + 3.60 so...
0.9y + 3.6 + 0.75y = $13.50

Let's combine like terms:

0.9y + 0.75y = 1.65y so...

1.65y + 3.6 = $13.50

Let's subtract 3.6 from both sides:

1.65y = $9.90

Let's divide both sides by 1.65 to get y by itself.

y = 6

Now that we know how many bars (y) were bought we can plug this into our second equation to find out how many cones were bought. We know there were 4 more cones than bars and we wrote it out as:

x = y + 4

Plugging in 6, which is the value we solved for y, in for y we get:

x = 6 + 4

Solving we get:

x + 10

Our final answer is x = 10, 10 cones were bought and
y = 6, 6 bars were bought.

You can check your answer by plugging these values into either equation. Hope this helps...Good Luck with your Math.

Answer 2

Let "c" equal the number of cones bought. Let "b" equal the number of bars bought. We're told 4 more cones than bars were bought, so c= 4+b. If cones are 90 cents and bars are 75 cents, then 0.90*c + 0.75*b should give the total amount spent. We're told this is $13.50. So now we have two equations to worth with:

c = 4+b
0.90*c + 0.75*b = 13.50

Now it's just a matter of solving two equations with two unknowns. Substitute c in the second equation with "4+b", then solve that second equation for b. Once you have this value, add 4 to it to find c. That value of C is going to be your answer.

Answer 3

how about hints instead of solving your homework for you

Let's let the number of bars bought= x
therefore, the number of cones bought = x+? (you answer)

The total price paid = price of a cone x number of cones + price of a bar x number of bars

plug in the numbers
then solve for x
then tell me how many bars were bought
then how many cones were bought

Answer 4

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Answer 5

let x be the number of cones bought
let y be the number of bars bought

.9x + .75y = 13.5

since four more cones than bars were bought then

x = y + 4

so you have two equations and two unknowns

.9x + .75y = 13.5 and
x - y = 4

multiply the bottom equation by -.9 and subtract if from the top

.9x + .75y = 13.5
-.9x+.9y = -3.6

0x +1.65y = 9.9, divide both sides by 1.65

y = 6, so 6 bars were bought

x = y + 4 so 10 cones were bought

Answer 6

x= bars
x+4= cones
.9(x+4)+.75x = 13.5
.9x+3.6 +.75x =13.5
1.65x = 9.9
x = 6
x+4 = 10 = number of cones

Answer 7

let a = # of cones
let a+4= # of bars

.9a+.75(a+4)=13.50
.9a+.75a+3=13.50
1.65a+3=13.50
.65a=10.50
???? haha sorry I tried

Answer 8

x = bars

x + 4x = 13.50
500X = 1350

Assign one in relationship to the other, set to amount then SOLVE !!