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square root of 3x divided by the square root of x minus the square root of 3

2007-01-17 04:56:00 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

you need to find the least common denominator... which would be square root of x

then multiply the whole thing, top and bottom by square root of x...

this would cancel out the bottom square root of x

leaving you with... 3x(square root of x)-square root of 3(square root of x)

and continue reducing.

(this is if i read your equation right... i couldnt tell if you meant minus the square root of 3 was also in the denominator or outside the fraction given)

2007-01-17 05:04:19 · answer #1 · answered by tootsfloat4 1 · 0 0

well first your should square the numerator and the demononator so it becomes 3x over x- square root of three but then u still have a square root in the demonomator so u need to multiply sqaure root of three to the numerator and the demononator to get rid of that now you can slove the problem

2007-01-21 11:14:42 · answer #2 · answered by Rosie 2 · 0 0

sqrt(3x) /(sqrt x -sqrt 3) .Multiplicate numerator and deominator by tje conjugate = sqrtx+ sqrt 3 so you obtain
sqrt(3x) *( sqrt x+ sqrt3)/ (x-3)

2007-01-17 13:59:56 · answer #3 · answered by santmann2002 7 · 0 0

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