Algebra Help please?

Question

Add or Subtract as indicated:

a-1/a+1 + a+1/a-1

Answer 1

a - 1/a + 1 + a +1/a - 1

a + 1 + a - 1 - 1/a + 1/a

a + a + 1 - 1 +1/a - 1/a
-or-
a + a + 1 + (-1) +1/a + (-1/a)

2a (the fractions and ones cancel one another out)

Answer 2

I think this requires parenthesis, since order of operations necessitates the divisions before the additions/subtractions. Your questions reads like a-(1/a) + a + (1/a) -1. If my guess is right, your spacing was smart, and the problem is actually [(a-1) / (a+1)] + [(a+1) / (a-1)].

You have to get a common denominator, which is (a+1) x (a-1), or a^2 - b^2.

Multiplying, (a-1)x(a-1) / (a+1)x(a-1) + (a+1)x(a+1) / (a+1)x(a-1)

Further, (a^2 - 2a +1) / (a^2 - b^2) + (a^2 + 2a + 1) / (a^2 - b^2)

Combining, (a^2 - 2a + 1 + a^2 + 2a + 1) / (a^2 - b^2)

Finally, (2a^2 + 2) / (a^2 - b^2)

Answer 3

a-1/a+1 + a+1/a-1

First, simplify the "a"s. You have a+a which is 2a.
Next, simplify the 1/a. You have -1/a+1/a which is 0.
Then simplify the numbers. You have 1-1 which is 0.

So, this is equivalent to 2a.

Answer 4

The easiest way is to separate them into like 'terms'. Then you get:
a + a + 1/a - 1/a + 1 -1

from that you can see that the 1/a's as well as the 1's simply cancel out and you are left with two a's

so.... the answer is 2a

ta da...

.

Answer 5

a- 1/a+1+a+1/a-1
(-1/a+1/a=0
1-1=0
a+a=2a)
answer : 2a

Answer 6

im not sure,but i think a=0.i had a 99 A in algebra,but that was over 2 years ago and i havent done problems like that in a while.see if any1 else also gets the answer.sorry if its wrong.i dont remember exactly how to do those equations.

Answer 7

Honey, who needs Math with looks like mine?

Answer 8

= (a-1)2 + (a+1)2
------------------
(a-1)*(a+1)

= a2 + 1 - 2a + a2 + 1 + 2a
----------------------------------
a2 - b2

= 2(a2+1)
-------------
a2 - b2

{the 2 after a is supposed to be a superscript.. it means a square}