If m = 788 and c = 3
What does E =
2007-01-17 02:58:47 · 7 answers · asked by 22sa 3 in Science & Mathematics ➔ Mathematics
E=M(c^2)
E = 788 x 3^2
E = 788 x 9
E = 7092
:) Have fun!
2007-01-17 03:03:56 · answer #1 · answered by Rizeel 1 · 0⤊ 0⤋
E=788*3^2=7092
2007-01-17 03:06:34 · answer #2 · answered by rwbblb46 4 · 0⤊ 0⤋
First the 788 g or kg?
I use first kg more easy with MKSA 1kg = 1MKSA
E = 788* (3*10^8)^2 =7.09*10^19 J
if 788g
E = 7.09 10^16 J
2007-01-17 03:12:23 · answer #3 · answered by maussy 7 · 0⤊ 0⤋
m=788kg (mass)
c=3*10^8m/s
E=788*(3*10^8)^2=7.092*10^19 joules
2007-01-17 03:12:36 · answer #4 · answered by foxy 1 · 0⤊ 0⤋
E = 7092 according to your equation.
c is a constant so it should be c= 3 x 10^8 m/s
so really E = 7092 x 10^16
2007-01-17 03:04:09 · answer #5 · answered by E 5 · 0⤊ 0⤋
But in einstein's equation c=3*10^8
2007-01-17 03:04:58 · answer #6 · answered by Tariq M 3 · 0⤊ 0⤋
Don't you own a calculator????
See, this is a thumbs-down question!!!!!!!!!!!
2007-01-17 03:01:07 · answer #7 · answered by Melissa Me 7 · 0⤊ 1⤋