Simplify:
3a+b/6a+2b
Add or Subtract as indicated:
b/b-1 + 2b/b^2-1
2007-01-17 02:56:39 · 4 answers · asked by S.H.I.E.L.D. 1 in Education & Reference ➔ Homework Help
Thank you for all your help, I'm sorry I posted the wrong one for the second problem, the one I'm having trouble with is actually this one:
a-1/a+1 + a+1/a-1
2007-01-17 03:54:31 · update #1
Try this website
http://www.webmath.com/
you put the problem in and they solve it.
For the first problem break the problem down like this
3a + b/ 2(3a+b)....then you can take out the 3a + b so you would have 1/2 that is what I get but you might want to check it.
The second one use the webmath page...
2007-01-17 03:03:35 · answer #1 · answered by blu_drgn25 4 · 0⤊ 0⤋
is the 3a+b together? or is that 3 seperate terms, the second one is just 1/b - 1
2007-01-17 03:02:04 · answer #2 · answered by poseidenneptune 5 · 0⤊ 0⤋
3a+b/6a+2b = 3a+b/2(3a+b)
= 1/2
b/b-1 + 2b/b^2-1 = b/(b-1) + 2b/(b+1)(b-1)
= [ b(b+1) + 2b ] / (b+1)(b-1)
= b(b+3)/(b+1)(b-1)
2007-01-17 03:03:46 · answer #3 · answered by illustration 3 · 0⤊ 0⤋
www.alegbrahelp.com best website in world trust me
2007-01-17 02:59:43 · answer #4 · answered by ? 1 · 0⤊ 0⤋