A table costs Rs 200 more than the chair.The price of 2 tables and 3 chairs is Rs 1400.Find the cost of each.?

Question

vikas is three years older than Deepika.Six years ago,Vikas's age was four times Deepika's age.Find the ages of Deepika and Vikas.

Answer 1

T = 200 + C------------------(1)
2T + 3C = 1400-------------(2)

replacing T in (2) by its value from (1)
2(200+C) + 3C =1400
400 + 2C + 3C = 1400
5C = 1000 => C = 200
T = 400

V = 3 + D-------------------(1)
(V-6)=4(D-6)---------------(2)

replacing V in (2) by its value from (1)
(3 + D - 6) = 4(D-6)
D- 3 = 4D - 24
3D = 21 => D = 7 and V = 10

Answer 2

T=Tables C=Chairs

T=C+200
2T+3C=1400

2(C+200)+ 3(200)=1400
2C+400+600=1400
2C=400
C=200
T=C+200 T=200+200
T=400

Chairs=200 Tables= 400

Answer 3

The tables are 400, the chairs 200.

(2 x 400) + (3 x 200) = 1400

Deepika is 7, Vikas is 10.

Answer 4

Ans 1>
cost of Table = cost of chair + Rs. 200

t= c + 200

two tables + three chairs costs Rs. 1400

2t + 3c = 1400

2 * ( c + 200 ) + 3c = 1400

5c + 400 = 1400

5c =1000

c = 200
t = 200 + 200 = 400

cost of one chair 200
cost of one table 200


Ans 2>

Vikas is three years older them Deepika so

v = 3 + d

Six years ago

(v-6) = 4 * (d-6)

(3+d-6)=4 * (d-6)

d-3 = 4d-24

3d = 21

d = 7

v = 10

Present Age 10, 9

Answer 5

let the chair's cost be "x"
and let the table's cost be "x+200"

So,therefore,

3(x) + 2(x+200)=1400
3x+2x+400=1400
5x=1000,(taking 400 on the other side)
so therefore,x=200(dividing 1000 by 5)

so there fore,chair's cost = x = Rs.200
and table's cost= x+200=200+200=Rs.400

2nd question:
v=vikas and d=deepika
v=d+3
(v-6)=4(d-6)
as we know v=d+3
so therefore
d+3-6=4d-24
d-3=4d-24
21=3d
so therefore , d=deepika=7(21/3)
and v=vikas=d+3=7+3=10
so ages of vikas and deepika are
deepika=7 years
vikas=10 years.

Answer 6

T = 200 +C
2T +3C=1400
T-C=200
Solving Eqn 2 and 3
3T+2C=1600
Solving We have T=400 and C=200

Vikas =x
Deepika =x-3
Six years ago Vikas's age=x-6
Six years ago Deepika's age=x-3-6
By condition
x-6=4(x-3-6)
x-6=4(x-9)
-3x=-30
x=10
Therefore Deepika's age =x-3=7

Answer 7

1) chair + 200 = table
we can multiplicate this equation with 3

3 chairs + 600 = 3 tables


3 chairs - 3 tables = -600
-
3 chairs +2 tables = 1400

-5tables = -2000
tables = -2000/(-5) = 400 Rs
& chairs = 400 - 200= 200 Rs

2) first equation :
vidkas = 3 + deepika
vidkas - deepka = 3

second equation:
vidkas - 6 = 4 (deepka-6)
vidka = 4 deepka -24 + 6
vidka - 4 deepka = -18

lets substract these 2 equations:

vidkas - deepka = 3
vidka - 4deepka = -18

3 deepka = 21
deepka = 7 years

let's replace deepka = 7 in the first equation to find vidka:

vidka - 7 = 3
vidka = 10years

Answer 8

Table = t
chair =c

c+200=t
2t + 3c =1400
2(c+200) + 3c=1400
2c+400 +3c =1400
5c = 1000
c =200

200 + 200 =400
t= 400

Deepika = d
Vikas = v

d +3 =v
v-6 =4(d-6)
d + 3 -6 = 4d -24
21 =3d
d = 7
7+ 3 =10
10 =v

So in conclusion: Table =400, Chair =200
Deepika = 7, Vikas =10

There You Go!

Answer 9

It t is table and c is chair then t-c = 200.
2t + 3c = 1400. Solve these 2 eqautions simultaneously to get the answer t=400 and c = 200

V = vikas, d = deepika
v-d = 3
v-6 = 4(d-6)
Therefore v = 10 and d = 7

Answer 10

1.cost of table=rs 400
chair=rs 200

2. vikas age. = 9year
deepika age = 6 year

Answer 11

Cost of Chair = 200Rs
Table = 400Rs


Age of Vikas = 10years
Deepika = 7years