If someone could help that would be great!
2007-01-17 02:12:14 · 4 answers · asked by kate m 1 in Science & Mathematics ➔ Mathematics
theta = 4 would be slightly greater than pi, but less than 3pi/2, which is greater than 4.5. So it is in the third quadrant, because the line theta = pi marks the boundary between quadrants 2 and 3. The reference angle would be 4 - pi, the angle from theta = 4 to the negative horizontal.
2007-01-17 02:18:23 · answer #1 · answered by DavidK93 7 · 1⤊ 0⤋
You need to know that the first quadrant is the angles from 0 to pi/2 = 1.57..., the second quadrant is the angles from pi/2 to pi = 3.14..., the 3rd quadrant is the angles from pi to 1.5pi = 4.71..., and the 4th quadrant is the angles from 1.5 pi to 2pi.
So then, theta= 4 is in the 3rd quadrant.
The reference angle is the acute angle from theta to the X-axis, in this case that is from 4 back to pi. Reference angle = 4 - pi = 0.8584...
2007-01-17 10:25:00 · answer #2 · answered by morningfoxnorth 6 · 0⤊ 0⤋
If you mean 4 degrees, it's obviously in quadrant I.
If you mean 4 radians, the reference angle is
4 - Ï. Since Ï < 4 < 3Ï/2, this angle is in the 3rd
quadrant.
2007-01-17 10:20:49 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
if the angle of theta is 4 degrees it is in thje first quadrant
if
2007-01-17 12:47:56 · answer #4 · answered by gjmb1960 7 · 0⤊ 0⤋