sudesh is twice as old as seema.If six years is subtracted from seema's age and four years are added to sudesh's age,sudesh will be four times seema's age.How old were they 3 years ago?
2007-01-17 01:58:53 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x = 2y
4(y-6) = 4+x
4y-24 = 4 + 2y
2y = 28
y = 14, x = 28
They were 11 and 25 three years ago.
2007-01-17 02:04:37 · answer #1 · answered by gebobs 6 · 2⤊ 0⤋
Let Sudesh be X and Seema be Y.
Given X = 2Y and 4(Y-6) = X+4
=> 4Y-24 = X+4
=> 4Y-24 = 2Y+4 (since X = 2Y)
=> 4Y-2Y = 4+24
=> 2Y = 28
=> Y = 28/2
=> Y = 14
Sub Y = 14 in X = 2Y
=> X = 2*14
=> X = 28
Therefore at present Sudesh age is 28 and Seema's age is 14
Sudesh's age was 25 and Seema's age was 14 three years ago.
2007-01-19 20:19:19 · answer #2 · answered by sathiya 1 · 0⤊ 0⤋
let present age of seema=x yrs
sudesh=2x yrs
atq
4(x-6)=2x+4
4x-24=2x+4
4x-2x=4+24
2x=28
x=28/2
x=14
present age of seema=14 yrs
present age of sudesh=28 yrs
3 yrs ago age of seema=11 yrs
3 yrs ago age of sudesh=25 yrs
seema was 11 yrs old and sudesh was 25 yrs old three yrs ago
2007-01-17 02:21:41 · answer #3 · answered by friend 1 1 · 0⤊ 0⤋
seema=x
sudesesh=2x
4(x-6)=2x+4
4x-24=2x+4
2x=28
x=14
seema=11
sudesh=25
2007-01-17 02:05:32 · answer #4 · answered by Maths Rocks 4 · 0⤊ 0⤋