2 dice are thrown one red one blue.the scores on their faces are added Determine which if either is greater?

Question

a) the probability that total score is 10or more given that red dice shows a 6.
b) the probability that total score is 10or more given that at least one of the dice shows a 6.
Can the answer to( b) be 5/11

Answer 1

both are equal as the probablity will be the same in both cases
if one duce is six the other dice must show 4 5 or 6 to score 10 or more . A probability of 50% in both cases

Answer 2

a) Given that the red die is a 6, then the blue die has to be 4, 5 or 6. Probability = 1/2.

b) given that at least one of the dice is a 6, we have one of the following cases (blue + red):
1+6, 2+6, 3+6, 4+6, 5+6, 6+6,
6+1, 6+2, 6+3, 6+4, 6+5.
That's 11 equally probable cases, 5 of which have a total of at least 10. Answer: 5/11.

Answer 3

If the red dice shows 6, then the blue dice has six possiblilities. Only 4, 5, and 6 will give you more than ten. So, probability of having ten or more given that the red dice is showing 6 is 0.5 or a 50% chance. That should answer the first part of the question.

Answer 4

start with (a)

possible outcomes are blue = 1, 2, 3, 4, 5, 6 while red = 6. gives 6 possible combinations. right?

and Sum => 10 only if blue = 4, 5, or 6 so probability is 3 out of 6



then (b)

possible outcomes are

let first # be red, second # be blue

(6, 1), (6, 2), (6,3), (6,4), (6,5), (6,6)
(1, 6), (2, 6), (3,6), (4,6), (5,6), (6,6)

but notice the last combination for each row is the same.

for a total of 11 possible combinations. Since only 5 have sum =>10
so probability = 5/11