A ray of light passing through (1,2 )reflects on x axis at A&reflected ray pass through (5,3) Find A?

Answer 1

You have one ray that passes through (1,2) and (A,0). A second ray passes through (A,0) and (5,3). Because it's reflection of light, the angle of incidence equals the angle of reflection. That means that the slopw of one line is the negative of the slope of the other line. So if the slope of the first line is M, then the slope of the second line is -M. Now solve for the equations of the lines passing through two points, which has the general formula (y2 - y1) = m(x2 - x1)

For the line passing through (1,2) and (A,0), with slope M, you have
(2-0) = M(1-A)

For the line passing through (A,0) and (5,3), with slope -M, you have
(0-3) = -M(A-5)

Now you have two equations with two unknowns (M and A), and it's easy to solve for A

Answer 2

Call (1,2) point B and (5,3) point C

Since the ray reflects at A, you know that the slope b/w A and B is negative of the slope b/w A and C

since A is on the x axis, you can call the coordinates of A to be (x,0)

Now (0-2)/(x-1) = -(3-0)/(5-x)
so -2(5-x) = -3(x-1)
-10+2x = -3x+3
x = 13/5

so A = (13/5 , 0)

Answer 3

The slope of (1,2) to (A,0) is negative to the slope of (A,0) to (5,3). Therefore:

-(-2/(A - 1)) = 3/(5 - A)

2/(A - 1) = 3/(5 - A)

2(5 - A) = 3(A - 1) { Multiplied both sides by (5 - A)(A - 1) }

10 - 2A = 3A - 3

5A = 13

A = 13/5 = 2.6

Answer 4

If A coordinate is (x,0), we have

2/(x-1)=3/(5-x)

10 - 2 x = 3 x - 3
13 = 5 x
x = 13/5, so A is the point (13/5,0).

Answer 5

find the point on the X axis (A) that has the same angle to 1,2 as it does to 5,3. That will be your answer

Answer 6

seen mild rays have wavelengths sufficiently small to "see" the glass no longer as a sheet yet as a chain of atoms and molecules with various empty area in between. Glass, like various substance has extra empty area than actual fabric interior it. till a variety of mild waves hits a particle in glass (which isn't likely), it passes by using it.