2007-01-17 01:07:26 · 5 answers · asked by JinJin1967 1 in Science & Mathematics ➔ Mathematics
504 if the digits do not repeat. 729 if they do.
2007-01-17 01:12:06 · answer #1 · answered by Francisco D 2 · 0⤊ 0⤋
I think that the answer is 729. Think of a lock where the numbers go from 0 to 9 with three spinners - this gives 1000 combinations.
However, if it's content, not sequence, my answer is wrong. Since you want combinations of 3 numbers (3 spinners) and the numbers are from 1 to 9 (there are 9 digits) I simply cube 9.
2007-01-17 01:13:03 · answer #2 · answered by thevideogamecenter 1 · 0⤊ 0⤋
comb of 9 taken by 3 = 9*8*7 /6 = 84
2007-01-17 07:11:24 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
With or without repetition?
Combination with repetition is (9+3-1)!/3!(9-1)! = 165
Combination without repetition is 9!/(3!6!) = 84
Permutations with repetition is 9^3 = 729
Permutations without repetition is 9!/6! = 504
2007-01-17 01:13:24 · answer #4 · answered by gebobs 6 · 0⤊ 0⤋
9*9*9
=729
2007-01-17 01:10:23 · answer #5 · answered by openpsychy 6 · 0⤊ 1⤋