Suppose the series is 1/2 + 1/3 + 1/5 + 1/7 + 1/11 + . . . + 1/Pn.
t has been known for quite a long time that, although the terms converge to zero, the sum diverges. It is asymptotic to ln(ln(Pn)).
2007-01-17 01:42:56
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answer #1
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answered by Anonymous
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The people who are saying "converges to 0" are mixing up the concept of sequence and series. The sequence 1/Pk converges to 0. The series sum(1/Pk) diverges to positive inifinity as other posters indicated.
2007-01-17 04:52:37
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answer #2
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answered by a_math_guy 5
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if me memory of cal 2 is correct this is a divergent series.
even though 1/Pk>1/P(k+1)...eventually 1/Pk--->0
but each 1/Pk adds something more to the series.
So the series never reaches a finite val.
2007-01-17 01:14:13
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answer #3
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answered by Tharu 3
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This series diverges. See the following website,
where you will find five proofs of this:
http://en.wikipedia.org/wiki/Proof_that_the_sum_of_the_reciprocals_of_the_primes_diverges
On the other hand, it is also known that the
sum of the reciprocals of all twin primes is convergent
(or perhaps finite).
2007-01-17 02:14:01
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answer #4
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answered by steiner1745 7
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It is convergent to 0. Each term in Pk increases to infinity, so 1/Pk approaches o as k increases.
2007-01-17 00:52:51
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answer #5
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answered by JasonM 7
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Pk is positively increasing so the denominator in 1/Pk is continuously positively increasing so the set converges to zero :)
2007-01-17 01:05:31
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answer #6
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answered by fate_n83 3
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2016-11-24 23:01:59
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answer #7
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answered by Erika 4
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