an elevator can hold 20 people of 75 kg. The elevator has a mass of 500 kg. the maximum force the elevator can withstand is 29,6000N. What is the greatest acceleration the elevator's motor can produce without breaking the cable?
2007-01-16 21:52:12 · 4 answers · asked by will p 1 in Science & Mathematics ➔ Mathematics
mass of people = 20*75 = 1500kg
mass of elevator = 500 kg
total mass = 1500+500
=2000kg
Given , F = 29,6000N
Since F = ma,
a = F/m
=29,6000/2000
=148m/s^2
2007-01-16 23:22:22 · answer #1 · answered by loally 2 · 0⤊ 0⤋
Total mass= 500+ 20*75 = 2000kg.Force = 29,6 N( seems too small)
In any case Newton states Force= mass* accel so
accel= force/mass.
You should put in the right numbers
2007-01-17 07:18:49 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
Use Force = Mass x Accleration. I think....all you have to do is put Force = 29,600N
Mass = 500kg
and then find Acc. by dividing force by mass.
--again i'm not sure.
The question is kinda weird...is it asking what is the greatest acc. it can have with 20 people on it...or with 500kg on it. that depends.
20 people all weighing 75kg would make the total weight be 1500kg so u would have to use that for mass.
EDIT: OH i read that wrong...the Elevators weight is 500kg..ok that works..the person who answered below me has the right thing.
2007-01-17 06:01:43 · answer #3 · answered by Cre-Ve 2 · 0⤊ 0⤋
assume G Force is 10, than force down is
Fdown = ((20*75)+500)*10 = 20.000 N
Fmax up = 29.600 N
F result= Fmax up - Fdown =9.600N
speed max is F result/mass people+lift=9.600/2000 = 4.8 m/s^2
2007-01-17 06:11:03 · answer #4 · answered by ave 2 · 0⤊ 0⤋