b) 15/4
You should write the brackets right:
f(x) = (4x² - 1) / x²
f(-2) = (16-1)/4 = 15/4
2007-01-16 19:50:34
·
answer #1
·
answered by anton3s 3
·
1⤊
0⤋
F(-2)=4*-2^2 - 1/-2^2
=16-1/4
=15/4
2007-01-17 02:00:35
·
answer #2
·
answered by SNK 1
·
1⤊
0⤋
f(x) = 4x^2 - 1 / x^2
f(-2) = 4*4 - 1 / 4
= 16-1 /4
=15/4
hence, (b) is the answer.
2007-01-16 20:19:28
·
answer #3
·
answered by arunima 2
·
1⤊
0⤋
Please use parenthesis and/or brackets. Do you mean
f(x) = (4x^2-1)/(x^2)?
First: the problem gives you the value for "x" > replace "x" with
- 2...
f(- 2) = [4(-2)^2-1]/[(-2)^2]
Sec: solve according to order of operations > PEMDAS > >>
( ), exponents, multiplication, division, addition & subtraction...
f(- 2) = [4(4)-1]/4
f(- 2) = [16 - 1]/4
f(- 2) = 15/4
2007-01-17 03:42:02
·
answer #4
·
answered by ♪♥Annie♥♪ 6
·
0⤊
0⤋
I guess that you mean (4x^2-1)/x^2
(-2)^2 = -2 * (-2) = 4. Remember: (-) * (-) = +
The numerator is 4*4 - 1 = 15
And the numerator is 4
So, the right answer is b
And
2007-01-16 19:53:51
·
answer #5
·
answered by MathTutor 6
·
0⤊
0⤋
f(x)=4x^2-1/x^2
f(-2)
= 4(-2)^2-1/(-2)^2
= 4 *4 -1/4
= 16 - 1/4
= 63/4 or 15.75
2007-01-16 19:38:47
·
answer #6
·
answered by Kinu Sharma 2
·
0⤊
1⤋
definitely answer (b)
Sequence of solving math problems as follow:
1: powers of
2: multiply or divides
3: Adding or subtraction
;)
2007-01-16 19:58:51
·
answer #7
·
answered by aldandooon 1
·
0⤊
0⤋