Suppose you have displayed a sine wave with V = Vosin(wt) on the screen, where Vo=5V and 2=5kHz. Assume further that the signal triggers the scope when V=2.5V and wt=30.
EXAMPLE:
Suppose you double the amplitude of the wave without changing any oscilloscope settings. What are V and wt now when the scope is triggered? [Answer: the level hasn't changed so the scope still triggers when V=2.5V. V=2.5=10sin(wt); wt=sin^–1(2.5/10)=14.4775121851511.]
QUESTION:
Assume that you reduce Vo back to 5 V and switch the trigger slope polarity from '+' to '-' without changing the trigger level dial. What are V and wt when the scope is triggered now?
2007-01-16
19:14:14
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3 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Physics