(physics)
2007-01-16 18:36:53 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
If water is stored in a tank and a small opening is made in the tank wall 1 ft below the water surface, the water will spout from the opening with a velocity of 8.02 ft/s. This velocity has the same magnitude that a freely falling rock attains after falling 1 ft. Similarly, at openings 4 ft and 8 ft below the water surface, the velocity of the spouting water will be 16.04 and 22.68 ft/s, respectively. Thus, the velocity of water leaving an opening under a given head, h, is the same as the velocity that would be attained by a body falling that same distance. The equation that shows how velocity changes with h and defines velocity head is:
2007-01-16 18:39:57 · answer #1 · answered by David 6 · 0⤊ 0⤋
water and any other liquid dont have "standard velocity", but if water is flowing many factors affects its velocity... viscosity, roughness of the surface its in contact, height of water....and many others...
but i'm definitely sure theres no standard velocity of water....
2007-01-17 04:10:56 · answer #2 · answered by dexterblueice 2 · 0⤊ 0⤋
To be honest.....I didn't know that water had a "standard velocity"!
2007-01-17 02:56:50 · answer #3 · answered by Mez 6 · 0⤊ 0⤋
Depends on your pipe size.
For 1" pipe, 6-8 m/s is reccommended.
2007-01-17 02:42:04 · answer #4 · answered by tgypoi 5 · 0⤊ 0⤋
the velocity as mentioned before is affected by many factors. most of them are mentioned above. please do not forget the Reynolds number that indicates the measure of turbulance and its side effects.
2007-01-17 07:44:16 · answer #5 · answered by Emmanuel P 3 · 0⤊ 0⤋