2007-01-16 18:15:34 · 6 answers · asked by cryprt_keep07 1 in Science & Mathematics ➔ Mathematics
AB + BC = AC (assuming this is a line not a triangle)
3x + 5x = 8
8x = 8
x = 1
2007-01-16 18:20:15 · answer #1 · answered by Jim Burnell 6 · 0⤊ 0⤋
If ABC are the sides of right triangle
AB = 3x, BC =5x, AC =8?
AB^2 + BC^2= AC^2
(3x)^2 + (5x)^2= 82
9x^2 + 25x^2= 64
34x^2 =64
x^2 =32/17
x = sqrt (32/17)
2007-01-17 02:27:07 · answer #2 · answered by Kinu Sharma 2 · 0⤊ 0⤋
Following non-equation statements are correct about a triangle always:
2007-01-17 02:42:04
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answer #3
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answered by Robert 2
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AB+AC>BC
AB+BC>AC
AC+BC>AB
then:
3x+8>5x
3x+5x>8
5x+8>3x
then 1
You have given the values of AB, BC and AC. What is the question?
2007-01-17 02:20:09 · answer #4 · answered by mani 2 · 1⤊ 0⤋
if you r talking about trianglers.. it will be as following:
|AC|^2 = |AB|^2 + |BC|^2
|AC|^2 = 9(x^2) + 25 (x^2)
|AC|^2 = 34 (x^2)
64 = 34 (x^2)
64/34 = x^2
x = SQRT(64/34)
:)
2007-01-17 02:38:43 · answer #5 · answered by aldandooon 1 · 0⤊ 0⤋
You need to find out whether you need to solve the equation in terms of x=..A....and x=B... and x=C...
or
A=B....x and B=A....x etc
2007-01-17 02:23:32 · answer #6 · answered by Samasoniasso 1 · 0⤊ 0⤋