Question on bond angles?

Question

A molecule of hydrogen cyanide contains 1 hydrogen atom, 1 carbon, and 1 nitrogen. The carbon is bonded to the hydrogen atom and to the nitrogen atom. Predict the bond angle in this molecule?

Answer 1

The bond angle between H and C is 180 degrees and the bond angle between C and N is also 180 degrees. Thus, it is a linear molecule with C forming one bond with H and 3 bonds with N.

It looks like this: H ─ C ≡ N:

Note that H has 2 electrons around it which is good, C has an octet and N has a total of octet, with one lone pair

Answer 2

Remember VSEPR. the carbon atom has 4 bonds, 3 to the nitrogen and 1 to the hyrdogen. This gives you 2 groups and no unshared pairs of electrons. The furthest apart these can get is 180 degrees (a straight line.)

Answer 3

Bond angles are got here upon by utilising understanding the form of electron density (places the place there are electrons) factors. Linear molecules: C=O=C 2 places to discover electrons so bond perspective formed is a hundred and eighty for molecules like BCl3 that are arranged in a triangle the bond perspective may be one hundred twenty For molecules in a tetrahedral association (CH4) the bond angles are approximately 109.5 yet once you have lone pairs like in H2O .. :O-H I H The bond perspective is slightly much less. approximately 104 however the foremost way bond perspective is set is by utilising the molecular geometry of the molecule itself. There are molecules with greater complicated sp3d and sp3d2 molecular preparations yet i merely dealt with the effortless ones. in case you want greater help deliver me a query or 2 and that i will attempt to help.

Answer 4

its a linear molecule:
H-C=N (its actually a triple bond between C and N but I couldn't show it) so the angle is 180 degrees.

Answer 5

180 degrees