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This is a real-world problem and not somebody's homework or some stumper of a trick question. I know it's not hard but I can't quite remember how to do it. We have a combination lock at work. I do not know how old it is, but nobody knows the combination. It has 5 buttons, 1 through 5, and the combination is a 4-digit one with repetition allowed.

So how many possible combinations are there? If there's not too many I'll just try 'em all. Not much to do there sometimes.

2007-01-16 18:04:43 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

10 answers

With one repition allowed:

5 x 5 x 4 x 3

which = 300

You have 5 choices for the first one and one other (because of repitition) and then 4 for the third and 3 for the last.

With repition allowed for all:

5 x 5 x 5 x 5 = 625

It's unclear if you meant one repetition or any repetition..

Either way... Pretty time consuming...

2007-01-16 18:27:52 · answer #1 · answered by Jaqua 2 · 2 1

If the lock has 5 buttons, then there are 5 choices for hitting the first button. If repetition is allowed, then there are also 5 choices for each of the other 3 hits that need to be done. Thus the answer is 5^4 = 625 combinations.

2007-01-16 18:23:59 · answer #2 · answered by falzoon 7 · 2 0

5 x 5 x 5 x 5 = 625 different combinations

2007-01-16 18:35:56 · answer #3 · answered by Kinu Sharma 2 · 2 0

I thik it's 5^4 = 625 combinations

2007-01-16 18:24:32 · answer #4 · answered by Andri 2 · 2 0

5 x 5 x 5 x 5 = 625 different combinations

(each time you press a digit, you have five different choices)

2007-01-16 18:14:25 · answer #5 · answered by Anonymous · 2 0

5*5*4*3*2

2007-01-16 23:07:23 · answer #6 · answered by Anonymous · 0 1

The answer is 5^4 = 625.

2007-01-16 18:14:47 · answer #7 · answered by Northstar 7 · 1 2

Simply, if you have 1 repetation/ button, you can get the following:

first attemp: 5 choices

second attemp: 5 choices

third attemp: 4 choices

forth attemp: 4 choices

that equals 400 compinations

if you ment you can repete only one digit of the choices you had

first attemp: 5 choices

second attemp: 5 choices

third attemp: 5 choices

forth attemp: 4 choices

and that equals 500 compinations

so you can choose :)

2007-01-16 18:57:58 · answer #8 · answered by aldandooon 1 · 1 2

5^4

625

(sorry, at first I thought it was 5 digit code)

2007-01-16 18:13:26 · answer #9 · answered by sspade30 5 · 2 0

there is a lot i am not sure a thousand it would take you a long time just break the lock

2007-01-16 18:14:33 · answer #10 · answered by mastermind 1 · 0 5

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