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I have to find derivative of : (ln x)^2

I got 2x but i dont think i did anything with ln

2007-01-16 17:57:38 · 6 answers · asked by ??? 2 in Science & Mathematics Mathematics

6 answers

y = (ln x)^2
let u = ln x
du/dx = d/dx (ln x) = 1/x

y = u^2
dy/du = d/du (u^2) = 2u = 2 ln x

dy/dx = dy/du * du/dx
= 2 ln x * 1/x
= 2/x * ln x

2007-01-16 18:08:09 · answer #1 · answered by Kinu Sharma 2 · 0 0

lnx^2
=2/x

rule: y=ln x^n
dy/dx= n/x

2007-01-16 18:07:42 · answer #2 · answered by Anonymous · 0 1

anti spinoff is merely the different of spinoff meaning merely the different of differentiation. for the above situation upload a million and subtract a million in the numerator x+a million-a million/x+a million wish you spotted that the cost doesnt exchange now (x+a million)-a million/x+a million now placing apart a million - a million/x+a million now it turns into less demanding essential of a relentless ithink u comprehend and essential of a million/x+a million is log(a million/x+a million) so the respond would be x-log(a million/x+a million)

2016-12-16 06:34:42 · answer #3 · answered by woolf 4 · 0 0

(2*ln x)/x

2007-01-16 18:01:17 · answer #4 · answered by fleisch 4 · 0 0

Answer:
{d((lnx)^2)/d(lnx)}* {d(lnx)/dx}
= 2*{ln(x)}/x

2007-01-16 18:04:58 · answer #5 · answered by dipu 1 · 0 0

d{(ln x)²}/dx = (2ln x)/x

2007-01-16 18:12:09 · answer #6 · answered by Northstar 7 · 0 0

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