how do u solve these log problems? My teacher totally skipped this portion of the chapter and still assigned it for homework.
a. log^3y 64= 2
b. log^5 (y^2+44)= 3
show your work please
2007-01-16 17:36:11 · 4 answers · asked by Creb 2 in Education & Reference ➔ Homework Help
I can try this.....
I am not sure I understand a i am assuming a base of 3:
log^3 y*64 = 2
I guess you have to know this rule.
log^3 x = log^10 x / log^10 3
I just converted from base 3 to base 10 which is easier to work with
so log^10 y64 / log^10 3 = 2
log^10 y64 = 2 * log^10 3
y64 = 10^ (2*log^10 3)
y64 = 9
y = 9/64
Or you can do this....
3^ log^3 y64 = 3^2
y64 = 9
b.
5 ^ (log^5 (Y^2+44) = 5^3
y^2+44 = 125
y^2 = 81
y = +/- 9
2007-01-16 18:18:06 · answer #1 · answered by nicewknd 5 · 1⤊ 0⤋
Get the log terms on one side, all other terms on the other side of the equals sign. Then raise both sides to the power of the base of the logs. General example:
a*logA + b = c; move non-log terms all to the right:
logA = (c - b)/a; if log is base 10, then place both sides as an exponent of 10:
10^logA = 10^[(c - b)/a]; But 10^logA = A, so
A = 10^[(c - b)/a]
2007-01-16 18:13:26 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
Solve y by algebra and use anti-log to get into y.
2007-01-16 18:04:02 · answer #3 · answered by wacky_racer 5 · 1⤊ 0⤋
try algebra ?
2007-01-16 18:51:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋