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election for mayor in town x, candidates are jones,smith &lee. in the poll 200 voters were selected at random. 82 votes for jones , 38 for smith, 59 for lee and 21 undecided. if there are 30,000 voters , how many votes can each candidate expect?

2007-01-16 17:26:11 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

multiply everything by 30,000/200 = 150.
So, for Jones(j), Smith(s), Lee(l)
82 x 150 = 12300
38 x 150 = 5700
59 x 150 = 8850

Ok, now for the undecided, we must assume that the probability of them choosing candidate (j,s,l) corresponds to the percent of the votes the candidate got in the poll. For example, Jones got 82/179. So, multiply THAT fraction to the undecided votes TOTAL (21 x 150 = 3150 x 82/179 = 1443)
Do the same for the others:
s = 38/179 x 3150 = 669
l=59/179 x 3150 = 1038

Add those to the totals:
j=12300 + 1443 = 13743
s=5700 + 669 = 6369
l= 8850 + 1038 = 9888

Add them all together to check that their sum = 30,000
13743 + 6369 + 9888 = 30,000 *sweet*
I'm assuming that every VOTER, votes. Which seems very logical since on election day if they VOTE they must actually vote, they can't put undecided then. LOL

2007-01-16 17:41:42 · answer #1 · answered by Ace 4 · 0 0

there are 30,000 voters and you polled 200. Divide 30000 / 200 and get 150. Then multiply each result by 150 to get their expected vote total

Jones 82 * 150 = 12300
Smith 38 * 150 = 4700
Lee 59 * 150 = 8850
Undecided 21 * 150 = 3150

2007-01-17 01:39:14 · answer #2 · answered by Bill F 6 · 0 0

Jones: 82/200 x100= 41%
41% of 30,000
= ( 41 x 30,000)/100
= 41 x 300
= 12,300

Lee: 59/200 x100= 29.5%
29.5% of 30,000
= ( 29.5 x 30,000)/100
= 29.5 x 300
= 8,850

Smith: 38/200 x 100 = 19%
19% of 30,000
= ( 19 x 30,000)/100
= 19 x 300
= 5,700

Undecided: 21/200 x 100 = 10.5%
10.5% of 30,000
= ( 10.5 x 30,000)/100
= 10.5 x 300
= 3,150
Thus,
Jones = 12,300 Votes
Lee = 8,850 Votes
Smith = 5,700 Votes
Undecided = 3,150 Votes
Check:
12,300 + 8,850 + 5,700 + 3,150 = 30,000 Votes

2007-01-17 02:02:17 · answer #3 · answered by Kinu Sharma 2 · 0 0

Each voter represents 0.5 % of a vote. Divide the number of voters by 2 to find out what percentage of the vote each candidate will receive. Divide each percentage by 100 to give you a decimal and then multiply each decimal by 30 000. You should find, for example, that Jones should receive 12 300 votes.

2007-01-17 01:33:21 · answer #4 · answered by balderarrow 5 · 0 0

take the percentage and then apply it to the larger population

jones: 82/200 x100= 41%
41% of 30,000 = 12,300
lee: 59/200 x100= 29.5%
29.5% of 30,000 = 8,850
smith: 38/200 x 100 = 19%
19% of 30,000 = 5,700

2007-01-17 01:36:05 · answer #5 · answered by Anonymous · 0 0

jones should expect = 30000*82/200=12300 votes.

smith should expect = 30000*38/200=5700 votes

lee should expect = 30000*59/200 = 8850 votes

2007-01-17 01:37:58 · answer #6 · answered by Anonymous · 0 0

jones, 82/200=.41(41%)
smith, 38/200=.19(19%)
lee, 59/200=.295(29.5%)
undecided 21/200=.105(10.5%)
therefore:
jones, 41% or 30,000x.41=12,300
smith, 19% or 30,000x.19=5,700
lee, 29.5% or 30,000x.295=8,850
and
undecided, 10.5% or 30,000x.105=3,150

2007-01-17 01:37:32 · answer #7 · answered by Scott O 3 · 0 0

Jones = 41%
Smith = 19%
Lee=29.5%
Undecided=10.5%

Jones =.41(30000) = 12300
Smith=.19(30000)=5700
Lee = .295(30000)=8850
Undecided=.105(30000)=3150

2007-01-17 01:40:33 · answer #8 · answered by Anonymous · 0 0

Actually they solve it..... good work guyz

2007-01-17 03:03:51 · answer #9 · answered by aldandooon 1 · 0 1

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