Here is the problem...
10. Find the distance from R(-7, 8) to the line with the equation y = 5.
2007-01-16 17:16:53 · 4 answers · asked by bourbon91c 2 in Education & Reference ➔ Homework Help
Step 1:Since the equation of a line is y=mx+c and in the problem the equation of line is y=5, the value of x=0.
Step 2:Value of y will be 5 as you can see from the equation.
Now we know two points R(-7,8) and (0,5). Apply distance formula
you will get the answer as square root of 58.
2007-01-16 17:23:27 · answer #1 · answered by muthu 2 · 0⤊ 1⤋
Looks like Pyntagorean theorem,
3(square) + 7(square) = distance(square)
where, in the plot, 3 came from (8-5) on y and -7 on x,
and so, 9 + 49 = d(square)
and square root of 58 = d
so, d = 7.6157
2007-01-17 01:36:09 · answer #2 · answered by wacky_racer 5 · 0⤊ 0⤋
It will be a vertical line from the y-coordinate of the point to y=5. So 3 units.
2007-01-17 01:19:47 · answer #3 · answered by treseuropean 6 · 0⤊ 0⤋
the answer is 3. Use the point (-7,5) that is the shortest distance to the line. You can still use the distance formula and get the square root of 9.
2007-01-17 01:28:31 · answer #4 · answered by trichbopper 4 · 0⤊ 0⤋