solve. x√3 - 3x = 5?

Question

PLEASE HELP. show step by step ? :]]

Answer 1

Yeah ok chagee's way is easier.

x(√3 - 3) = 5

x = 5/(√3 - 3) x (√3 + 3)/(√3 + 3)
= (5√3 + 15)/(3 - 9)
= -(5√3 + 15)/6

Answer 2

First: factor-find the least common denominator which is, "x"
*Factor out the "x" & multiply it by the remaining terms to get the original expression...

x(V`3 - 3) = 5

Sec: solve for "x" by isolating it on one side > divide both sides by >>> V`3 - 3

[x(V`3 - 3)]/(V`3 - 3) = 5/(V`3 - 3)

*Cross cancel "like" terms...

x = 5/(V`3 - 3)

Third: rationalize the denominator > multiply the conjugate expression of V`3 - 3 (V`3 + 3) with the numerator and denominator....

x = [5(V`3 + 3)]/[(V`3 - 3)(V`3 + 3)]

x = (5V`3 + 15)/[(V`9) + 3V`3 - 3V`3 - 9)]

x = (5V`3 + 15)/(3 - 9)

x = (5V`3 + 15)/(-6)

x = (5V`3/-6) + (15/-6)

x = (- 5/6V`3) - 5/2

Or, -(5√3 + 15)/6

Answer 3

x(√3 - 3) = 5
x = 5 / (√3 - 3)
Rationallisatoin it
x = 5/(√3 - 3) x (√3 + 3)/(√3 + 3)
x = (5√3 + 15)/(3 - 9)
x = -(5√3 + 15)/6

Answer 4

x√3 - 3x = 5 can be written as:
-x(3- √3)= 5 which leads to:
x= - 5/(3- √3) or - (5/6) (3 + √3) Answer.

Answer 5

So you want to solve

x sqrt(3) - 3x = 5

Factor x.

x(sqrt(3) - 3)) = 5

Now, divide both sides by sqrt(3) - 3.

x = 5/[sqrt(3) - 3]

However, we NEVER want a radical in the denominator, by proper math etiquette. What we have to do is multiply the denominator by its conjugate, [sqrt(3) + 3]. Doing this will eliminate the square root symbol, because it will form a difference of squares. We have to multiply the numerator by this value too.

x = 5[sqrt(3) + 3] / [3 - 9]
x = 5[sqrt(3) + 3]/(-6)

Therefore

x = (-5/6) (sqrt(3) + 3)

Answer 6

x√3 - 3x = 5
x(√3-3)=5
x=5/(√3-3)=-3.94
or
x=5(√3+3)/(3-9)
x=5(√3+3)/(-6)

Answer 7

The approximate value of square root of 3 is 1.732....

x* 1.732-3x=5
1.732x-3x=5
-1.268x=5
x= 5/-1.268
= -3.943

Answer 8

x(3^(1/2)-3)=5
x=5/(3^(1/2)-3)

Answer 9

puggy's answer is best

Answer 10

lol oops