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I need them ALL, every last one and they must be correct. PLEASE!!???

2007-01-16 16:21:37 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

11 answers

The prime factorization of 36 is

36 = (2^2)(3^2)

All you have to do is write out all permutations of each of the powers, which are both 2.

(2^0)(3^0), (2^1)(3^0), (2^0) (3^1), (2^1)(3^1), (2^2)(3^1), (2^1)(3^2), (2^2)(3^2)

Note the pattern of the powers: (0, 0), (1, 0), (0, 1), (1, 1), (2, 1),(1, 2), (2, 2)

Analytical math aside, your factors are just the calculations of them.

(2^0)(3^0) = 1
(2^1)(3^0) = 2
(2^0) (3^1) = 3
(2^1)(3^1) = 6
(2^2)(3^1) = 12
(2^1)(3^2) = 18
(2^2)(3^2) = 36

2007-01-16 16:29:05 · answer #1 · answered by Puggy 7 · 1 0

Just find pairs of numbers which when multiplied together gives 36.

Start with 1 until you get a repeated number.
1 x 36 = 36
2 x 18 = 36
3 x 12 = 36
4 x 9 = 36
5 cannot be
6 x 6 = 36
7 cannot be
8 cannot be
9 is already above [STOP]

Thus, the factors are
1, 2, 3, 4, 5, 6, 9, 12, 18, 36

2007-01-16 16:54:35 · answer #2 · answered by dkrudge 2 · 0 0

The factors of 36 can be any of the following :

1 * 36
2 * 18
3 * 12
4 * 9
6 * 6

2007-01-16 17:20:13 · answer #3 · answered by Anonymous · 0 0

factors of 36 are,

1 and 36
2 and 18
3 and 12
4 and 9
6 and 6

2007-01-16 16:27:37 · answer #4 · answered by loally 2 · 1 0

Factors Of 36

2016-10-02 22:38:59 · answer #5 · answered by banowski 4 · 0 0

factors are the numbers which can divide 36
factors are in pairs
1) 1*36=36
2) 2*18=36
3) 3*12=36
4) 4*9=36
5) not divisible by 5
6) 6*6=36
7) not divisible by 7
8) not divisible by 8
9) 9 has already occured with 4
(remember no number should be repeated !!)

So factors are
1 and 36
2 and 18
3 and 12
4 and 9
6 and 6

2007-01-16 16:37:58 · answer #6 · answered by Anonymous · 0 0

1, 2, 3, 4, 6, 9, 12, 18, 36

Here's the way to tackle problems like this:
1) Find the square root of the number, which in this case sqrt(36) = 6. If your number is not a perfect square, such as 34, then you know that 5 2) Check if the integers from 1 to that square root are divisible by your number. For 36, you would check up to and including 6. For 34, you would check up to and including 5.
3) With your current list of divisible numbers, divide 36 by each of them.
4) The set of all factors of your number is the union of both lists, i.e. both lists together.

2007-01-16 16:24:50 · answer #7 · answered by sesquipedalian 3 · 1 0

1, 2, 3, 4, 6, 9, 12, 18 & 36.

2007-01-16 17:07:22 · answer #8 · answered by yupchagee 7 · 0 0

factors of 36 are
1,2,3,4,6,9,12,18 and 36

2007-01-16 18:43:38 · answer #9 · answered by Kinu Sharma 2 · 0 0

First tell me all of the factors that entered into the decision to not do your own homework. Lazyface.

2007-01-16 16:28:23 · answer #10 · answered by Clauzilla 4 · 1 1

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