Find three consecutive integers whose sum is -12. Thanks a lot!
2007-01-16 16:05:07 · 13 answers · asked by katerina 1 in Science & Mathematics ➔ Mathematics
Whenever you have a problem that tells you to find three consecutive integers whose sum is A, you do this:
x + (x + 1) + (x + 2) = A
in your case,
x + (x + 1) + (x + 2) = -12
so 3x + 3 = -12
3x = -15
x = -5
x + 1 = -4
x + 2 = -3
2007-01-16 16:08:06 · answer #1 · answered by Biznachos 4 · 0⤊ 0⤋
Three consecutive numbers whose sum is 12 are 3,4,5.
But your question is -12,
So, the answer is -3,-4,-5
2007-01-16 16:15:30 · answer #2 · answered by loally 2 · 0⤊ 0⤋
-3+-4+-5=-12
2007-01-16 16:13:27 · answer #3 · answered by <3 makes the world go round 3 · 0⤊ 0⤋
- 3 (+) - 4 (+) -5 = -12
2007-01-20 16:08:08 · answer #4 · answered by Anonymous · 0⤊ 0⤋
-3-4-5
2007-01-16 16:07:32 · answer #5 · answered by frozenbrew 4 · 1⤊ 0⤋
-3 -4 -5
2007-01-16 16:19:40 · answer #6 · answered by HeadAche 3 · 0⤊ 0⤋
If I could do this then maybe I wouldnt be 30 years old working at 7-11.
No just kidding, but seriously I couldnt tell you what in the world an integer is!
2007-01-16 16:08:30 · answer #7 · answered by Anonymous · 0⤊ 0⤋
-3*4
2007-01-16 16:10:09 · answer #8 · answered by Bridget 4 · 0⤊ 0⤋
-3, -4, -5
2007-01-16 16:13:50 · answer #9 · answered by lucky 2 · 0⤊ 0⤋
-3, -4, -5
2007-01-16 16:12:18 · answer #10 · answered by hazz r. 1 · 0⤊ 0⤋